I = .5*F mA
In this equation, I is the current flowing through the VCC_CKLK and GND_CKLK pins, and F is the frequency output of the phase-locked loop (PLL). Therefore, if you are driving a 25 MHz clock into an active ClockBoost circuit, typical current consumption would be:
I = .5 * 50 = 25 mA
If you are using the ClockLock and ClockBoost circuits simultaneously, you can compute current consumption only if you are using ClockBoost. For example, if you are using the ClockLock and ClockBoost circuits simultaneously with a 25 MHz input (50 MHz output of the PLL), I = 25 mA.